Python Basic - 1: Exercise-146 with Solution
A Python list contains two positive integers. Write a Python program to check whether the cube root of the first number is equal to the square root of the second number.
Sample Data:
[[8, 4]] -> True
[[64, 16]]
-> True
[[64, 36]] -> False
Sample Solution-1:
Python Code:
def test[nums]:
x = nums[0]
y = nums[1]
t = y**0.5
if[x == t*t*t]:
return True
else:
return False
nums = [8, 4]
print["Original list of positive numbers:"]
print[nums]
print[test[nums]]
print["Check square root and cube root of the said numbers:"]
nums = [64, 16]
print["Original list of positive numbers:"]
print[nums]
print["Check square root and cube root of the said numbers:"]
print[test[nums]]
nums = [64, 36]
print["Original list of positive numbers:"]
print[nums]
print["Check square root and cube root of the said numbers:"]
print[test[nums]]
Sample Output:
Original list of positive numbers: [8, 4] True Check square root and cube root of the said numbers: Original list of positive numbers: [64, 16] Check square root and cube root of the said numbers: True Original list of positive numbers: [64, 36] Check square root and cube root of the said numbers: False
Flowchart:
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Sample Solution-2:
Python Code:
def test[nums]:
return [[[nums[1] ** 0.5] ** 3] == nums[0]]
nums = [8, 4]
print["Original list of positive numbers:"]
print[nums]
print[test[nums]]
print["Check square root and cube root of the said numbers:"]
nums = [64, 16]
print["Original list of positive numbers:"]
print[nums]
print["Check square root and cube root of the said numbers:"]
print[test[nums]]
nums = [64, 36]
print["Original list of positive numbers:"]
print[nums]
print["Check square root and cube root of the said numbers:"]
print[test[nums]]
Sample Output:
Original list of positive numbers: [8, 4] True Check square root and cube root of the said numbers: Original list of positive numbers: [64, 16] Check square root and cube root of the said numbers: True Original list of positive numbers: [64, 36] Check square root and cube root of the said numbers: False
Flowchart:
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The following tool visualize what the computer is doing step-by-step as it executes the said program:
Python Code Editor:
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Next: Sum of the digits in each number in
a list is equal.
Python: Tips of the Day
Concatenating iterable to a single string:
>>> x = ["python","really", "rocks"] >>> " ".join[x] 'python really rocks'
In this post, we will see how to calculate the square and cube of every number of the given list of numbers. We will use map[] along with lambda expression for calculation.
Table of Contents
- Write a program in python to enter a number and print its square and cube?
- Post a Comment
- How do you calculate squares in Python?
- How do you find the square root and square of a number in Python?
- How do you find the cube of a number in Python?
- How do you cube all numbers in a list in Python?
Algorithm
Step 1: Declare a list of numbers
Step 2: Find the square of number by multiplying the number itself two times.
Step 3: Print the numbers with square value
Step
4: Find the cube of number by multiplying the number itself three times.
Step 5: Print the numbers with cube value
Step 6: End
Example
Input [1, 2, 3, 4, 5] Output Square of every number of the provided list: [1, 4, 9, 16, 25] Cube of every number of the provided list: [1, 8, 27, 64, 125]
Program
numbers = [1, 2, 3, 4, 5] print["List of numbers:"] print[numbers] print["\nSquare of every number of the provided list:"] square_numbers = list[map[lambda x: x ** 2, numbers]] print[square_numbers] print["\nCube of every number of the provided list:"] cube_numbers = list[map[lambda x: x ** 3, numbers]] print[cube_numbers]
Output
List of numbers: [1, 2, 3, 4, 5] Square of every number of the provided list: [1, 4, 9, 16, 25] Cube of every number of the provided list: [1, 8, 27, 64, 125]
HomePython ProgrammingPrint Square and Cube of Given number in Python
Write a program in python to enter a number and print its square and cube?
num=int[input["Enter any integer number: "]]
sq=num**2
print["Square of Given number: ",sq]
cube=num**3
print["Cube of Given number: ",cube]
Output:-
Enter any integer number: 5
Square of Given number: 25
Cube of Given number: 125
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Given a number, the task is to write a Python program to calculate square of the given number.
Examples:
Input: 4 Output: 16 Input: 3 Output: 9 Input: 10 Output: 100
We will provide the number, and we will get the square of that number as output. We have three ways to do so:
- Multiplying the number to get the square [N * N]
- Using Exponent Operator
- Using math.pow[] Method
Method 1: Multiplication
In this approach, we will multiply the number with one another to get the square of the number.
Example:
Python3
n = 4
square = n * n
print[square]
Output:
16
Method 2: Using Exponent Operator
In this approach, we use the exponent operator to find the square of the number.
Exponent Operator: **
Return: a ** b will return a raised to power b as output.
Example:
Python3
n = 4
square = n ** 2
print[square]
Output:
16
Method 3: Using pow[] Method
In this approach, we will use the pow[] method to find the square of the number. This function computes x**y and returns a float value as output.
Syntax: float pow[x,y]
Parameters :
x : Number whose power has to be calculated.
y : Value raised to compute power.
Return Value :
Returns the value x**y in float.
Example:
Python3
n = 4
square = pow[n, 2]
print[square]
Output:
16.0
How do you calculate squares in Python?
To calculate the square of a number in Python, we have three different ways..
By multiplying numbers two times: [number*number].
By using Exponent Operator [**]: [number**2].
Using math.pow[] method: [math.pow[number, 2]].
How do you find the square root and square of a number in Python?
sqrt[] function is an inbuilt function in Python programming language that returns the square root of any number. Syntax: math.sqrt[x] Parameter: x is any number such that x>=0 Returns: It returns the square root of the number passed in the parameter.
How do you find the cube of a number in Python?
Python Program to Find Cube of a Number.
def cube[x]:.
return x * x * x..
n = int[input[" Enter the number : "]].
cube1 = cube[n].
print["The Cube of {0} = {1}". format[n, cube1]].
How do you cube all numbers in a list in Python?
Given a list, the task is to write a python program to cube all the list elements..
Input: [1, 2, 3, 4].
Output: [1, 8, 27, 64].
Explanation: Cubing all the list elements..
Input: [2, 4, 6].
Output: [8, 64, 216].