Check if all elements in list are in another list python

Check if Python List Contains Elements of Another List

Contents

• 1 all[] method
• 2 any[] method
• 3 Custom search
• 4 set[] method

In the sample below, we are using two lists having overlapping values. One of these is the big one which holds all the elements of the second one.

• List1 – This listcontains all or some of the elements of another.
• List2 – It is a subset of the first one.

Now, we’ve to programmatically prove that the List1 contains the elements of the List2. There could be multiple ways to achieve it.

all[] method

To demonstrate that List1 has List2 elements, we’ll use the all[] method.

# Program to check the list contains elements of another list # List1 List1 = ['python' , 'javascript', 'csharp', 'go', 'c', 'c++'] # List2 List2 = ['csharp1' , 'go', 'python'] check = all[item in List1 for item in List2] if check is True: print["The list {} contains all elements of the list {}".format[List1, List2]] else : print["No, List1 doesn't have all elements of the List2."]

The output of the above code is as follows:

The list ['python', 'javascript', 'csharp', 'go', 'c', 'c++'] contains all elements of the list ['csharp', 'go', 'python']

any[] method

Another method is any[] which we can use to check if the list contains any elements of another one.

# Program to check the list contains elements of another list # List1 List1 = ['python' , 'javascript', 'csharp', 'go', 'c', 'c++'] # List2 List2 = ['swift' , 'php', 'python'] check = any[item in List1 for item in List2] if check is True: print["The list {} contains some elements of the list {}".format[List1, List2]] else : print["No, List1 doesn't have any elements of the List2."]

The output of the above code is as follows:

The list ['python', 'javascript', 'csharp', 'go', 'c', 'c++'] contains some elements of the list ['swift', 'php', 'python']

Custom search

In this method, we’ll write a custom search method to test if the first list contains the second one.While iterating the lists if we get an overlapping element, then the function returns true. The search continues until there is no element to match andreturns false.

# Program to check if a Python list contains elements of another list def list_contains[List1, List2]: check = False # Iterate in the 1st list for m in List1: # Iterate in the 2nd list for n in List2: # if there is a match if m == n: check = True return check return check # Test Case 1 List1 = ['a', 'e', 'i', 'o', 'u'] List2 = ['x', 'y', 'z', 'l', 'm'] print["Test Case#1 ", list_contains[List1, List2]] # Test Case 2 List1 = ['a', 'e', 'i', 'o', 'u'] List2 = ['a', 'b', 'c', 'd', 'e'] print["Test Case#2 ", list_contains[List1, List2]]

The output of the above code is as follows:

Test Case#1 False Test Case#2 True

set[] method

We’ll use the set[] method to convert the lists and call Python set intersection[] method to find if there is any match between the list elements.

# Program to check if a Python list contains elements of another list def list_contains[List1, List2]: set1 = set[List1] set2 = set[List2] if set1.intersection[set2]: return True else: return False # Test Case 1 List1 = ['a', 'e', 'i', 'o', 'u'] List2 = ['x', 'y', 'z', 'l', 'm'] print["Test Case#1 ", list_contains[List1, List2]] # Test Case 2 List1 = ['a', 'e', 'i', 'o', 'u'] List2 = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i'] print["Test Case#2 ", list_contains[List1, List2]]

The output of the above code is as follows:

Test Case#1 False Test Case#2 True

Python List Contains: How to Check If Item Exists in List

During development in Machine learning, AI, or even web development, we generally come across a problem where we need to test if the particular item from a given list lies as a sub-string or not. To check if the list contains the specific element or not in Python, use the“in”operator or“not in” operator. Let’s explore this topic in detail.

Python check if a list exists in another list

Now, we can see how to check if a list exists in another list in Python.

• In this example, I have taken a variable as a list and another variable as a check_list.
• And if condition is used if the check_list is present in the list then the output will be “List is present”, else “List is not present”.
• To get the output, I have used print[“List is present”].

Example:

list = [[1,5,7,], [2, 3, 4], [3, 6, 9], [4, 8, 12]] check_list = [2,3,4] if check_list in list: print["List is present"] else: print["List is not present"]

We can see the output as List is present. You can refer to the below screenshot for the output.

Python check if a list exists in another list

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Python | Check if one list is subset of other

Sometimes we encounter the problem of checking if one list is just an extension of the list i.e just a superset of one list. These kinds of problems are quite popular in competitive programming. Having shorthands for it helps the cause. Let’s discuss various ways to achieve this particular task.

Method #1: Using all[]function

all[] is used to check all the elements of a container in just one line. Checks for all the elements of one list for existence in other lists.

Python3

# Python3 code to demonstrate # to check if list is subset of other # using all[] # initializing list test_list = [9, 4, 5, 8, 10] sub_list = [10, 5, 4] # printing original lists print["Original list : " + str[test_list]] print["Original sub list : " + str[sub_list]] # using all[] to # check subset of list flag = 0 if[all[x in test_list for x in sub_list]]: flag = 1 # printing result if [flag]: print["Yes, list is subset of other."] else: print["No, list is not subset of other."]

Output :

Original list : [9, 4, 5, 8, 10] Original sub list : [10, 5, 4] Yes, list is subset of other.

Method #2 : Using set.issubset[]function

The most used and recommended method to check for a sublist. This function is tailor made to perform the particular task of checking if one list is a subset of another.

Python3

# Python3 code to demonstrate # to check if list is subset of other # using issubset[] # initializing list test_list = [9, 4, 5, 8, 10] sub_list = [10, 5] # printing original lists print["Original list : " + str[test_list]] print["Original sub list : " + str[sub_list]] # using issubset[] to # check subset of list flag = 0 if[set[sub_list].issubset[set[test_list]]]: flag = 1 # printing result if [flag]: print["Yes, list is subset of other."] else: print["No, list is not subset of other."]

Output :

Original list : [9, 4, 5, 8, 10] Original sub list : [10, 5] Yes, list is subset of other.

Method #3 : Using set.intersection[]function

Yet another method dealing with sets, this method checks if the intersection of both the lists ends up to be the sub list we are checking. This confirms that one list is a subset of the other.

Python3

# Python3 code to demonstrate # to check if list is subset of other # using intersection[] # initializing list test_list = [9, 4, 5, 8, 10] sub_list = [10, 5] # printing original lists print["Original list : " + str[test_list]] print["Original sub list : " + str[sub_list]] # using intersection[] to # check subset of list flag = 0 if[[set[sub_list] & set[test_list]] == set[sub_list]]: flag = 1 # printing result if [flag]: print["Yes, list is subset of other."] else: print["No, list is not subset of other."]

Output :

Original list : [9, 4, 5, 8, 10] Original sub list : [10, 5] Yes, list is subset of other.

Method #4 : Using iteration and counter

Using the count of elements in both lists to check whether the second list is a subset of the first list.

Python3

# Python3 code to demonstrate # to check if list is subset of other # Importing from collections import Counter def checkInFirst[a, b]: # getting count count_a = Counter[a] count_b = Counter[b] # checking if element exists in second list for key in count_b: if key not in count_a: return False if count_b[key] > count_b[key]: return False return True # initializing list a = [1, 2, 4, 5] b = [1, 2, 3] # Calling function res = checkInFirst[a, b] # Printing list print["Original list : " + str[a]] print["Original sub list : " + str[b]] if res == True: print["Yes, list is subset of other."] else: print["No, list is not subset of other."] # Added by Paras Jain[everythingispossible]

Output :

Original list : [1, 2, 4, 5] Original sub list : [1, 2, 3] No, list is not subset of other.

Method #5 : Using set index

Python3

# Python3 code to demonstrate # to check if list is subset of other # initializing list one = [1, 2, 3, 4, 5] two = [1, 2] # using set to find if element exists in another list result = set[x in one for x in two] flag = 0 for ans in result: if ans == False: flag = 1 # Printing list print["Original list : " + str[one]] print["Original sub list : " + str[two]] if flag == 0: print["Yes, list is subset of other."] else: print["No, list is not subset of other."] # Added by Paras Jain[everythingispossible]

Output :

Original list : [1, 2, 3, 4, 5] Original sub list : [1, 2] Yes, list is subset of other.

Method #6: Using functools.reduce

Python3

from functools import reduce from operator import and_ # main containing checker def contains[superset, subset] -> bool: # creates a list of boolean values and # combines them using the and operator return reduce[and_, [i in superset for i in subset]] # creating some lists for testing superset = [3, 4, 5, 6] subset = [4, 5] not_subset = [4, 5, 7] # print whether or not the # subset is in the superset print[f"{subset} is in {superset}: {contains[superset, subset]}"] print[f"{not_subset} is in {superset}: {contains[superset, not_subset]}"]

Output:

[4, 5] is in [3, 4, 5, 6]: True [4, 5, 7] is in [3, 4, 5, 6]: False

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Python Check If a List Contains Elements of Another List

June 26, 2021October 10, 2021 0 Comments check if any item in a list is in another list python, check if list contains same elements python, check if list is present in another list python, check if list is subset of another list python, python check if all elements in list are in another list, python check if any element in list is in another list, python check if list contains another list, python check if list contains elements of another list

In this tutorial, we are going to see how to check if a Python list contains all the elements of another list and display the result using the print[] function.

Suppose we have two lists, list1 and list2, like below.

list1 = ['Hi' , 'welcome', 'to', 'stackhowto'] list2 = ['to', 'stackhowto']

Check If a List Contains Elements of Another List Using all[] Methodcheck = all[item in list1 for item in list2] if check: print ["List1 contains all the elements of list2"] else : print ["List1 does not contain all the elements of list2"]

Output:

List1 contains all the elements of list2

The all[] function returns True if all the elements of an Iteration are true, otherwise it returns False.

Check If a List Contains Elements of Another List Using any[] Methodcheck = any[item in list1 for item in list2] if check: print ["List1 contains all the elements of list2"] else : print ["List1 does not contain all the elements of list2"]

Output:

List1 contains all the elements of list2

Python’s any[] function is one of the built-in functions. It takes the iterable as an argument and returns “True” if any of the elements is “True”. If the iterable is empty, it returns “False”.

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Python - Check if all elements in a list are identical

PythonServer Side ProgrammingProgramming

There may be occasions when a list will contain all the values which are same. In this article we will see various way to verify that.