1. Extract Elements From A Python List Using Index
Here in this first example, we created a list named ‘firstgrid’ with 6 elements in it. The print statement prints the ‘1’ element in the index.
firstgrid=["A","B","C","D","E","F"] print[firstgrid[1]]
Output: 'B'
2. Print Items From a List Using Enumerate
Here, we created a variable named ‘vara’ and we filled the elements into the list. Then we used ‘varx’ variable to specify the enumerate function to search for ‘1,2,5’ index positions.
vara=["10","11","12","13","14","15"] print[[varx[1] for varx in enumerate[vara] if varx[0] in [1,2,5]]]
Output: ['11', '12', '15']
Python Lists and List Manipulation
Michael Galarnyk
May 29, 2017·6 min read
Python Lists and List Manipulation Video
Before starting, I should mention that the code in this blog post and in the video above is available on my github.
Python – Extract elements from Ranges in List
Given a list, and a list of tuples with ranges, extract all elements in those ranges from list.
Input : test_list = [4, 5, 4, 6, 7, 5, 4, 5, 6, 10], range_list = [[2, 4], [7, 8]]
Output : [4, 6, 7, 5, 6]
Explanation : 4, 6, 7 are elements at idx 2, 3, 4 and 5, 6 at idx 7, 8.Input : test_list = [4, 5, 4, 6, 7, 5, 4, 5, 6, 10], range_list = [[2, 6]]
Output : [4, 6, 7, 5, 4]
Explanation : Elements from 2-6 index are extracted.
Method #1 : Using loop + list slicing
In this, we extract each range using list slicing and using loop iterate for each range and keep extending the extracting slices to extending list.
Python3
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# Python3 code to demonstrate working of # Extract elements from Ranges in List # Using loop + list slicing
# initializing list test_list = [4, 5, 4, 6, 7, 5, 4, 5, 4, 6, 4, 6, 9, 8]
# printing original list print["The original list is : " + str[test_list]]
# initializing ranges range_list = [[2, 4], [7, 8], [10, 12]]
res = [] for ele in range_list:
# extending ranges res.extend[test_list[ele[0] : ele[1] + 1]]
# printing result print["Ranges elements : " + str[res]] |
Output The original list is : [4, 5, 4, 6, 7, 5, 4, 5, 4, 6, 4, 6, 9, 8] Ranges elements : [4, 6, 7, 5, 4, 4, 6, 9]
Method #2 : Using list comprehension
In this, we apply similar method as above function, difference being that list comprehension is used to solve this in compact form.
Python3
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# Python3 code to demonstrate working of # Extract elements from Ranges in List # Using list comprehension from itertools import chain
# initializing list test_list = [4, 5, 4, 6, 7, 5, 4, 5, 4, 6, 4, 6, 9, 8]
# printing original list print["The original list is : " + str[test_list]]
# initializing ranges range_list = [[2, 4], [7, 8], [10, 12]]
# using one-liner to solve this problem res = list[chain.from_iterable[[test_list[ele[0] : ele[1] + 1] for ele in range_list]]]
# printing result print["Ranges elements : " + str[res]] |
Output The original list is : [4, 5, 4, 6, 7, 5, 4, 5, 4, 6, 4, 6, 9, 8] Ranges elements : [4, 6, 7, 5, 4, 4, 6, 9]
Article Tags :
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Python Program to Extract Elements from list in set
Given a list, the task is to write a Python Program to extract all the elements with its occurrence matching in set.
Input : test_list = [5, 6, 2, 3, 2, 6, 5, 8, 9], search_set = {6, 2, 8}
Output : [6, 2, 2, 6, 8]
Explanation : 2, 6 occur twice and in order with respect to other elements is output.
Input : test_list = [5, 6, 2, 3, 2, 6, 5, 8, 9], search_set = {8, 3, 5}
Output : [5, 3, 5, 8]
Explanation : 5 occurs twice and in order with respect to other elements is output.
Method #1 : Using loop
In this, each list element is iterated and checked for its presence in set using in operator and appended to result if found.
Python3
|
# Python3 code to demonstrate working of # Elements from list in set # Using loop
# initializing list test_list = [5, 6, 2, 3, 2, 6, 5, 8, 9]
# printing original list print["The original list is : " + str[test_list]]
# initializing search set search_set = {6, 2, 8}
res = [] for ele in test_list:
# check if element is present in set if ele in search_set: res.append[ele]
# printing result print["Set present list elements : " + str[res]] |
Output:
The original list is : [5, 6, 2, 3, 2, 6, 5, 8, 9] Set present list elements : [6, 2, 2, 6, 8]Method #2 : Using repeat[] + from_iterable[] + count[]
In this, we test for each set element in list and repeat using repeat[] by the count required to be computed using count[]. The order is not maintained in this result.
Python3
|
# Python3 code to demonstrate working of # Elements from list in set # Using repeat[] + from_iterable[] + count[] from itertools import chain, repeat
# initializing list test_list = [5, 6, 2, 3, 2, 6, 5, 8, 9]
# printing original list print["The original list is : " + str[test_list]]
# initializing search set search_set = {6, 2, 8}
# repeat repeats all the occurrences of elements res = list[chain.from_iterable[[repeat[ele, test_list.count[ele]] for ele in search_set]]]
# printing result print["Set present list elements : " + str[res]] |
Output:
The original list is : [5, 6, 2, 3, 2, 6, 5, 8, 9] Set present list elements : [6, 2, 2, 6, 8]Article Tags :
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Python Programs
Python list-programs
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Extract, replace, convert elements of a list in Python
Posted: 2020-10-28 / Tags: Python, List
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In Python, you can generate a new list by extracting, removing, replacing, or converting elements that meet the conditions of an existing list with list comprehensions.
This article describes the following contents.
- Basics of list comprehensions
- Apply operation to all elements of the list
- Extract/remove elements that meet the conditions from the list
- Replace/convert elements that meet the conditions in the list
See the following article for examples of lists of strings.
- Extract and replace elements that meet the conditions of a list of strings in Python
It is also possible to randomly sample elements from a list.
- Random sampling from a list in Python [random.choice, sample, choices]
Take the following list as an example.
l = list[range[-5, 6]] print[l] # [-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5]
source: list_select_replace.py
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