In which linked list first node contains previous address as the address of last node

Types of Linked List and Operation on Linked List

In the previous blog, we have seen the structure and properties of a Linked List. In this blog, we will discuss the types of a linked list and basic operations that can be performed on a linked list.

Types of Linked List

Following are the types of linked list

  1. Singly Linked List.
  2. Doubly Linked List.
  3. Circular Linked List.

Singly Linked List

A Singly-linked list is a collection of nodes linked together in a sequential way where each node of the singly linked list contains a data field and an address field that contains the reference of the next node.

The structure of the node in the Singly Linked List is

class Node { int data // variable to store the data of the node Node next // variable to store the address of the next node }

The nodes are connected to each other in this form where the value of the next variable of the last node is NULL i.e. next = NULL, which indicates the end of the linked list.

Doubly Linked List

A Doubly Linked List contains an extra memory to store the address of the previous node, together with the address of the next node and data which are there in the singly linked list. So, here we are storing the address of the next as well as the previous nodes.

The following is the structure of the node in the Doubly Linked List[DLL]:

class DLLNode { int val // variable to store the data of the node DLLNode prev // variable to store the address of the previous node DLLNode next // variable to store the address of the next node }

The nodes are connected to each other in this form where the first node has prev = NULL and the last node has next = NULL.

Advantages over Singly Linked List-

  • It can be traversed both forward and backward direction.
  • The delete operation is more efficient if the node to be deleted is given. [Think! you will get the answer in the second half of this blog]
  • The insert operation is more efficient if the node is given before which insertion should take place. [Think!]

Disadvantages over Singly Linked List-

  • It will require more space as each node has an extra memory to store the address of the previous node.
  • The number of modification increase while doing various operations like insertion, deletion, etc.

Circular Linked List

A circular linked list is either a singly or doubly linked list in which there are no NULL values. Here, we can implement the Circular Linked List by making the use of Singly or Doubly Linked List. In the case of a singly linked list, the next of the last node contains the address of the first node and in case of a doubly-linked list, the next of last node contains the address of the first node and prev of the first node contains the address of the last node.

Advantages of a Circular linked list

  • The list can be traversed from any node.
  • Circular lists are the required data structure when we want a list to be accessed in a circle or loop.
  • We can easily traverse to its previous node in a circular linked list, which is not possible in a singly linked list. [Think!]

Disadvantages of Circular linked list

  • If not traversed carefully, then we could end up in an infinite loop because here we don't have any NULL value to stop the traversal.
  • Operations in a circular linked list are complex as compared to a singly linked list and doubly linked list like reversing a circular linked list, etc.

Basic Operations on Linked List

  • Traversal: To traverse all the nodes one after another.
  • Insertion: To add a node at the given position.
  • Deletion: To delete a node.
  • Searching: To search an element[s] by value.
  • Updating: To update a node.
  • Sorting: To arrange nodes in a linked list in a specific order.
  • Merging: To merge two linked lists into one.

We will see the various implementation of these operations on a singly linked list.

Following is the structure of the node in a linked list:

class Node{ int data // variable containing the data of the node Node next // variable containing the address of next node }

Linked List Traversal

The idea here is to step through the list from beginning to end. For example, we may want to print the list or search for a specific node in the list.

The algorithm for traversing a list

  • Start with the head of the list. Access the content of the head node if it is not null.
  • Then go to the next node[if exists] and access the node information
  • Continue until no more nodes [that is, you have reached the null node]
void traverseLL[Node head] { while[head != NULL] { print[head.data] head = head.next } }

Linked List node Insertion

There can be three cases that will occur when we are inserting a node in a linked list.

  • Insertion at the beginning
  • Insertion at the end. [Append]
  • Insertion after a given node
Insertion at the beginning

Since there is no need to find the end of the list. If the list is empty, we make the new node as the head of the list. Otherwise, we we have to connect the new node to the current head of the list and make the new node, the head of the list.

// function is returning the head of the singly linked-list Node insertAtBegin[Node head, int val] { newNode = new Node[val] // creating new node of linked list if[head == NULL] // check if linked list is empty return newNode else // inserting the node at the beginning { newNode.next = head return newNode } }
Insertion at end

We will traverse the list until we find the last node. Then we insert the new node to the end of the list. Note that we have to consider special cases such as list being empty.

In case of a list being empty, we will return the updated head of the linked list because in this case, the inserted node is the first as well as the last node of the linked list.

// the function is returning the head of the singly linked list Node insertAtEnd[Node head, int val] { if[ head == NULL ] // handing the special case { newNode = new Node[val] head = newNode return head } Node temp = head // traversing the list to get the last node while[ temp.next != NULL ] { temp = temp.next } newNode = new Node[val] temp.next = newNode return head }
Insertion after a given node

We are given the reference to a node, and the new node is inserted after the given node.

void insertAfter[Node prevNode, int val] { newNode = new Node[val] newNode.next = prevNode.next prevNode.next = newNode }

NOTE: If the address of the prevNode is not given, then you can traverse to that node by finding the data value.

Linked List node Deletion

To delete a node from a linked list, we need to do these steps

  • Find the previous node of the node to be deleted.
  • Change the next pointer of the previous node
  • Free the memory of the deleted node.

In the deletion, there is a special case in which the first node is deleted. In this, we need to update the head of the linked list.

// this function will return the head of the linked list Node deleteLL[Node head, Node del] { if[head == del] // if the node to be deleted is the head node { return head.next // special case for the first Node } Node temp = head while[ temp.next != NULL ] { if[temp.next == del] // finding the node to be deleted { temp.next = temp.next.next delete del // free the memory of that Node return head } temp = temp.next } return head // if no node matches in the Linked List }

Linked List node Searching

To search any value in the linked list, we can traverse the linked list and compares the value present in the node.

bool searchLL[Node head, int val] { Node temp = head // creating a temp variable pointing to the head of the linked list while[ temp != NULL] // traversing the list { if[ temp.data == val ] return true temp = temp.next } return false }

Linked List node Updation

To update the value of the node, we just need to set the data part to the new value.

Below is the implementation in which we had to update the value of the first node in which data is equal to val and we have to set it to newVal.

void updateLL[Node head, int val, int newVal] { Node temp = head while[temp != NULL] { if[ temp.data == val] { temp.data = newVal return } temp = temp.next } }

Suggested Problems to solve in Linked List

  • Reverse linked list
  • Middle of the Linked List
  • Odd even linked List
  • Remove Duplicates from Sorted List
  • Merge Sort on Linked List
  • Check if a singly linked list is a palindrome
  • Detect and Remove Loop in a Linked List
  • Sort a linked list using insertion sort
  • Remove Nth Node from List End

Happy coding! Enjoy Algorithms.

Types of Linked List

A linked list is a linear data structure, in which the elements are not stored at contiguous memory locations. The elements in a linked list are linked using pointers. In simple words, a linked list consists of nodes where each node contains a data field and a reference[link] to the next node in the list.

Types Of Linked List

  • Singly Linked List: It is the simplest type of linked list in which every node contains some data and a pointer to the next node of the same data type. The node contains a pointer to the next node means that the node stores the address of the next node in the sequence. A single linked list allows traversal of data only in one way. Below is the image for the same:

  • Structure of Singly Linked List:
C++




// Node of a doubly linked list
class Node {
public:
int data;
// Pointer to next node in LL
Node* next;
};
Java




// Node of a doubly linked list
static class Node
{
int data;
// Pointer to next node in LL
Node next;
};
//this code is contributed by shivani
Python3




# structure of Node
class Node:
def __init__[self, data]:
self.data = data
self.next = None
C#




// Structure of Node
public class Node
{
public int data;
// Pointer to next node in LL
public Node next;
};
//this code is contributed by shivanisinghss2110
Javascript




// Node of a doubly linked list
class Node
{
constructor[]
{
this.data=0;
// Pointer to next node
this.next=null;
}
}
// This code is contributed by SHUBHAMSINGH10
  • Creation and Traversal of Singly Linked List:
C++




// C++ program to illustrate creation
// and traversal of Singly Linked List
#include
using namespace std;
// Structure of Node
class Node {
public:
int data;
Node* next;
};
// Function to print the content of
// linked list starting from the
// given node
void printList[Node* n]
{
// Iterate till n reaches NULL
while [n != NULL] {
// Print the data
cout data next;
}
}
// Driver Code
int main[]
{
Node* head = NULL;
Node* second = NULL;
Node* third = NULL;
// Allocate 3 nodes in the heap
head = new Node[];
second = new Node[];
third = new Node[];
// Assign data in first node
head->data = 1;
// Link first node with second
head->next = second;
// Assign data to second node
second->data = 2;
second->next = third;
// Assign data to third node
third->data = 3;
third->next = NULL;
printList[head];
return 0;
}
Java




// Java program to illustrate
// creation and traversal of
// Singly Linked List
class GFG{
// Structure of Node
static class Node
{
int data;
Node next;
};
// Function to print the content of
// linked list starting from the
// given node
static void printList[Node n]
{
// Iterate till n reaches null
while [n != null]
{
// Print the data
System.out.print[n.data + " "];
n = n.next;
}
}
// Driver Code
public static void main[String[] args]
{
Node head = null;
Node second = null;
Node third = null;
// Allocate 3 nodes in
// the heap
head = new Node[];
second = new Node[];
third = new Node[];
// Assign data in first
// node
head.data = 1;
// Link first node with
// second
head.next = second;
// Assign data to second
// node
second.data = 2;
second.next = third;
// Assign data to third
// node
third.data = 3;
third.next = null;
printList[head];
}
}
// This code is contributed by Princi Singh
C#




// C# program to illustrate
// creation and traversal of
// Singly Linked List
using System;
class GFG{
// Structure of Node
public class Node
{
public int data;
public Node next;
};
// Function to print the content of
// linked list starting from the
// given node
static void printList[Node n]
{
// Iterate till n reaches null
while [n != null]
{
// Print the data
Console.Write[n.data + " "];
n = n.next;
}
}
// Driver Code
public static void Main[String[] args]
{
Node head = null;
Node second = null;
Node third = null;
// Allocate 3 nodes in
// the heap
head = new Node[];
second = new Node[];
third = new Node[];
// Assign data in first
// node
head.data = 1;
// Link first node with
// second
head.next = second;
// Assign data to second
// node
second.data = 2;
second.next = third;
// Assign data to third
// node
third.data = 3;
third.next = null;
printList[head];
}
}
// This code is contributed by Amit Katiyar
Python3




# structure of Node
class Node:
def __init__[self, data]:
self.data = data
self.next = None
class LinkedList:
def __init__[self]:
self.head = None
self.last_node = None
# function to add elements to linked list
def append[self, data]:
# if linked list is empty then last_node will be none so in if condition head will be created
if self.last_node is None:
self.head = Node[data]
self.last_node = self.head
# adding node to the tail of linked list
else:
self.last_node.next = Node[data]
self.last_node = self.last_node.next
# function to print the content of linked list
def display[self]:
current = self.head
# traversing the linked list
while current is not None:
# at each node printing its data
print[current.data, end=' ']
# giving current next node
current = current.next
print[]
if __name__ == '__main__':
L = LinkedList[]
# adding elements to the linked list
L.append[1]
L.append[2]
L.append[3]
L.append[4]
# displaying elements of linked list
L.display[]
Javascript




// JavaScript program to illustrate
// creation and traversal of
// Singly Linked List
// Structure of Node
class Node
{
constructor[]
{
this.data=0;
this.next=null;
}
}
// Function to print the content of
// linked list starting from the
// given node
function printList[n]
{
// Iterate till n reaches null
while [n != null]
{
// Print the data
document.write[n.data + " "];
n = n.next;
}
}
// Driver Code
let head = null;
let second = null;
let third = null;
// Allocate 3 nodes in
// the heap
head = new Node[];
second = new Node[];
third = new Node[];
// Assign data in first
// node
head.data = 1;
// Link first node with
// second
head.next = second;
// Assign data to second
// node
second.data = 2;
second.next = third;
// Assign data to third
// node
third.data = 3;
third.next = null;
printList[head];
// This code is contributed by unknown2108
Output 1 2 3
  • Doubly Linked List: A doubly linked list or a two-way linked list is a more complex type of linked list which contains a pointer to the next as well as the previous node in sequence, Therefore, it contains three parts are data, a pointer to the next node, and a pointer to the previous node. This would enable us to traverse the list in the backward direction as well. Below is the image for the same:



  • Structure of Doubly Linked List:
C++




// Node of a doubly linked list
struct Node {
int data;
// Pointer to next node in DLL
struct Node* next;
// Pointer to the previous node in DLL
struct Node* prev;
};
Java




// Doubly linked list
// node
static class Node
{
int data;
// Pointer to next node in DLL
Node next;
// Pointer to the previous node in DLL
Node prev;
};
// This code is contributed by shivani
Python3




# structure of Node
class Node:
def __init__[self, data]:
self.previous = None
self.data = data
self.next = None
C#




// Doubly linked list
// node
public class Node
{
public int data;
// Pointer to next node in DLL
public Node next;
// Pointer to the previous node in DLL
public Node prev;
};
// This code is contributed by shivanisinghss2110
  • Creation and Traversal of Doubly Linked List:
C++




// C++ program to illustrate creation
// and traversal of Doubly Linked List
#include
using namespace std;
// Doubly linked list node
class Node {
public:
int data;
Node* next;
Node* prev;
};
// Function to push a new element in
// the Doubly Linked List
void push[Node** head_ref, int new_data]
{
// Allocate node
Node* new_node = new Node[];
// Put in the data
new_node->data = new_data;
// Make next of new node as
// head and previous as NULL
new_node->next = [*head_ref];
new_node->prev = NULL;
// Change prev of head node to
// the new node
if [[*head_ref] != NULL]
[*head_ref]->prev = new_node;
// Move the head to point to
// the new node
[*head_ref] = new_node;
}
// Function to traverse the Doubly LL
// in the forward & backward direction
void printList[Node* node]
{
Node* last;
cout NULL
push[&head, 1];
cout data = data;
ptr1->next = *head_ref;
// If linked list is not NULL then
// set the next of last node
if [*head_ref != NULL] {
while [temp->next != *head_ref] {
temp = temp->next;
}
temp->next = ptr1;
}
// For the first node
else
ptr1->next = ptr1;
*head_ref = ptr1;
}
// Function to print nodes in the
// Circular Linked List
void printList[Node* head]
{
Node* temp = head;
if [head != NULL] {
do {
// Print the data
cout data next;
} while [temp != head];
}
}
// Driver Code
int main[]
{
// Initialize list as empty
Node* head = NULL;
// Created linked list will
// be 11->2->56->12
push[&head, 12];
push[&head, 56];
push[&head, 2];
push[&head, 11];
cout next
= new_node->prev = new_node;
*start = new_node;
return;
}
// Pointer points to last Node
struct Node* last = [*start]->prev;
struct Node* new_node = new Node;
// Inserting the data
new_node->data = value;
// Update the previous and
// next of new node
new_node->next = *start;
new_node->prev = last;
// Update next and previous
// pointers of start & last
last->next = [*start]->prev
= new_node;
// Update start pointer
*start = new_node;
}
// Function to traverse the circular
// doubly linked list
void display[struct Node* start]
{
struct Node* temp = start;
printf["\nTraversal in"
" forward direction \n"];
while [temp->next != start] {
printf["%d ", temp->data];
temp = temp->next;
}
printf["%d ", temp->data];
printf["\nTraversal in "
"reverse direction \n"];
Node* last = start->prev;
temp = last;
while [temp->prev != last] {
// Print the data
printf["%d ", temp->data];
temp = temp->prev;
}
printf["%d ", temp->data];
}
// Driver Code
int main[]
{
// Start with the empty list
struct Node* start = NULL;
// Insert 5
// So linked list becomes 5->NULL
insertBegin[&start, 5];
// Insert 4 at the beginning
// So linked list becomes 4->5
insertBegin[&start, 4];
// Insert 7 at the end
// So linked list becomes 7->4->5
insertBegin[&start, 7];
printf["Created circular doubly"
" linked list is: "];
display[start];
return 0;
}
Java




// Java program to illustrate creation
// & traversal of Doubly Circular LL
import java.util.*;
class GFG{
// Structure of a Node
static class Node
{
int data;
Node next;
Node prev;
};
// Start with the empty list
static Node start = null;
// Function to insert Node at
// the beginning of the List
static void insertBegin[
int value]
{
// If the list is empty
if [start == null]
{
Node new_node = new Node[];
new_node.data = value;
new_node.next
= new_node.prev = new_node;
start = new_node;
return;
}
// Pointer points to last Node
Node last = [start].prev;
Node new_node = new Node[];
// Inserting the data
new_node.data = value;
// Update the previous and
// next of new node
new_node.next = start;
new_node.prev = last;
// Update next and previous
// pointers of start & last
last.next = [start].prev
= new_node;
// Update start pointer
start = new_node;
}
// Function to traverse the circular
// doubly linked list
static void display[]
{
Node temp = start;
System.out.printf["\nTraversal in"
+" forward direction \n"];
while [temp.next != start]
{
System.out.printf["%d ", temp.data];
temp = temp.next;
}
System.out.printf["%d ", temp.data];
System.out.printf["\nTraversal in "
+ "reverse direction \n"];
Node last = start.prev;
temp = last;
while [temp.prev != last]
{
// Print the data
System.out.printf["%d ", temp.data];
temp = temp.prev;
}
System.out.printf["%d ", temp.data];
}
// Driver Code
public static void main[String[] args]
{
// Insert 5
// So linked list becomes 5.null
insertBegin[ 5];
// Insert 4 at the beginning
// So linked list becomes 4.5
insertBegin[ 4];
// Insert 7 at the end
// So linked list becomes 7.4.5
insertBegin[ 7];
System.out.printf["Created circular doubly"
+ " linked list is: "];
display[];
}
}
// This code is contributed by shikhasingrajput
Python3




# structure of Node
class Node:
def __init__[self, data]:
self.previous = None
self.data = data
self.next = None
class DoublyLinkedList:
def __init__[self]:
self.head = None
self.start_node = None
self.last_node = None
# function to add elements to doubly linked list
def append[self, data]:
# is doubly linked list is empty then last_node will be none so in if condition head will be created
if self.last_node is None:
self.head = Node[data]
self.last_node = self.head
# adding node to the tail of doubly linked list
else:
new_node = Node[data]
self.last_node.next = new_node
new_node.previous = self.last_node
new_node.next = self.head
self.last_node = new_node
# function to print the content of doubly linked list
def display[self, Type = 'Left_To_Right']:
if Type == 'Left_To_Right':
current = self.head
while current.next is not None:
print[current.data, end=' ']
current = current.next
if current == self.head:
break
print[]
else:
current = self.last_node
while current.previous is not None:
print[current.data, end=' ']
current = current.previous
if current == self.last_node.next:
print[self.last_node.next.data, end=' ']
break
print[]
if __name__ == '__main__':
L = DoublyLinkedList[]
L.append[1]
L.append[2]
L.append[3]
L.append[4]
L.display['Left_To_Right']
L.display['Right_To_Left']
C#




// C# program to illustrate creation
// & traversal of Doubly Circular LL
using System;
public class GFG{
// Structure of a Node
public
class Node
{
public
int data;
public
Node next;
public
Node prev;
};
// Start with the empty list
static Node start = null;
// Function to insert Node at
// the beginning of the List
static void insertBegin[
int value]
{
Node new_node = new Node[];
// If the list is empty
if [start == null]
{
new_node.data = value;
new_node.next
= new_node.prev = new_node;
start = new_node;
return;
}
// Pointer points to last Node
Node last = [start].prev;
// Inserting the data
new_node.data = value;
// Update the previous and
// next of new node
new_node.next = start;
new_node.prev = last;
// Update next and previous
// pointers of start & last
last.next = [start].prev
= new_node;
// Update start pointer
start = new_node;
}
// Function to traverse the circular
// doubly linked list
static void display[]
{
Node temp = start;
Console.Write["\nTraversal in"
+" forward direction \n"];
while [temp.next != start]
{
Console.Write[temp.data + " "];
temp = temp.next;
}
Console.Write[temp.data + " "];
Console.Write["\nTraversal in "
+ "reverse direction \n"];
Node last = start.prev;
temp = last;
while [temp.prev != last]
{
// Print the data
Console.Write[ temp.data + " "];
temp = temp.prev;
}
Console.Write[ temp.data + " "];
}
// Driver Code
public static void Main[String[] args]
{
// Insert 5
// So linked list becomes 5.null
insertBegin[ 5];
// Insert 4 at the beginning
// So linked list becomes 4.5
insertBegin[ 4];
// Insert 7 at the end
// So linked list becomes 7.4.5
insertBegin[ 7];
Console.Write["Created circular doubly"
+ " linked list is: "];
display[];
}
}
// This code is contributed by 29AjayKumar
Output Created circular doubly linked list is: Traversal in forward direction 7 4 5 Traversal in reverse direction 5 4 7
  • Header Linked List: A header linked list is a special type of linked list which contains a header node at the beginning of the list. So, in a header linked list START will not point to the first node of the list but START will contain the address of the header node. Below is the image for Grounded Header Linked List:

  • Structure of Grounded Header Linked List:
C++




// Structure of the list
struct link {
int info;
// Pointer to the next node
struct link* next;
};
Python3




# structure of Node
class Node:
def __init__[self, data]:
self.data = data
self.next = None
Java




// Structure of the list
static class link {
int info;
// Pointer to the next node
link next;
};
// this code is contributed by shivanisinghss2110
C#




// Structure of the list
public class link {
public int info;
// Pointer to the next node
public link next;
};
// this code is contributed by shivanisinghss2110
  • Creation and Traversal of Header Linked List:
C++




// C++ program to illustrate creation
// and traversal of Header Linked List
#include
// #include
// #include
// Structure of the list
struct link {
int info;
struct link* next;
};
// Empty List
struct link* start = NULL;
// Function to create header of the
// header linked list
struct link* create_header_list[int data]
{
// Create a new node
struct link *new_node, *node;
new_node = [struct link*]
malloc[sizeof[struct link]];
new_node->info = data;
new_node->next = NULL;
// If it is the first node
if [start == NULL] {
// Initialize the start
start = [struct link*]
malloc[sizeof[struct link]];
start->next = new_node;
}
else {
// Insert the node in the end
node = start;
while [node->next != NULL] {
node = node->next;
}
node->next = new_node;
}
return start;
}
// Function to display the
// header linked list
struct link* display[]
{
struct link* node;
node = start;
node = node->next;
// Traverse until node is
// not NULL
while [node != NULL] {
// Print the data
printf["%d ", node->info];
node = node->next;
}
printf["\n"];
// Return the start pointer
return start;
}
// Driver Code
int main[]
{
// Create the list
create_header_list[11];
create_header_list[12];
create_header_list[13];
// Print the list
printf["List After inserting"
" 3 elements:\n"];
display[];
create_header_list[14];
create_header_list[15];
// Print the list
printf["List After inserting"
" 2 more elements:\n"];
display[];
return 0;
}
Java




// Java program to illustrate creation
// and traversal of Header Linked List
class GFG{
// Structure of the list
static class link {
int info;
link next;
};
// Empty List
static link start = null;
// Function to create header of the
// header linked list
static link create_header_list[int data]
{
// Create a new node
link new_node, node;
new_node = new link[];
new_node.info = data;
new_node.next = null;
// If it is the first node
if [start == null] {
// Initialize the start
start = new link[];
start.next = new_node;
}
else {
// Insert the node in the end
node = start;
while [node.next != null] {
node = node.next;
}
node.next = new_node;
}
return start;
}
// Function to display the
// header linked list
static link display[]
{
link node;
node = start;
node = node.next;
// Traverse until node is
// not null
while [node != null] {
// Print the data
System.out.printf["%d ", node.info];
node = node.next;
}
System.out.printf["\n"];
// Return the start pointer
return start;
}
// Driver Code
public static void main[String[] args]
{
// Create the list
create_header_list[11];
create_header_list[12];
create_header_list[13];
// Print the list
System.out.printf["List After inserting"
+ " 3 elements:\n"];
display[];
create_header_list[14];
create_header_list[15];
// Print the list
System.out.printf["List After inserting"
+ " 2 more elements:\n"];
display[];
}
}
// This code is contributed by 29AjayKumar
Python3




# structure of Node
class Node:
def __init__[self, data]:
self.data = data
self.next = None
class LinkedList:
def __init__[self]:
self.head = Node[0]
self.last_node = self.head
# function to add elements to header linked list
def append[self, data]:
self.last_node.next = Node[data]
self.last_node = self.last_node.next
# function to print the content of header linked list
def display[self]:
current = self.head.next
# traversing the header linked list
while current is not None:
# at each node printing its data
print[current.data, end=' ']
# giving current next node
current = current.next
# print[self.head.data]
print[]
if __name__ == '__main__':
L = LinkedList[]
# adding elements to the header linked list
L.append[1]
L.append[2]
L.append[3]
L.append[4]
# displaying elements of header linked list
L.display[]
C#




// C# program to illustrate creation
// and traversal of Header Linked List
using System;
public class GFG{
// Structure of the list
public class link {
public int info;
public link next;
};
// Empty List
static link start = null;
// Function to create header of the
// header linked list
static link create_header_list[int data]
{
// Create a new node
link new_node, node;
new_node = new link[];
new_node.info = data;
new_node.next = null;
// If it is the first node
if [start == null] {
// Initialize the start
start = new link[];
start.next = new_node;
}
else {
// Insert the node in the end
node = start;
while [node.next != null] {
node = node.next;
}
node.next = new_node;
}
return start;
}
// Function to display the
// header linked list
static link display[]
{
link node;
node = start;
node = node.next;
// Traverse until node is
// not null
while [node != null] {
// Print the data
Console.Write["{0} ", node.info];
node = node.next;
}
Console.Write["\n"];
// Return the start pointer
return start;
}
// Driver Code
public static void Main[String[] args]
{
// Create the list
create_header_list[11];
create_header_list[12];
create_header_list[13];
// Print the list
Console.Write["List After inserting"
+ " 3 elements:\n"];
display[];
create_header_list[14];
create_header_list[15];
// Print the list
Console.Write["List After inserting"
+ " 2 more elements:\n"];
display[];
}
}
// This code is contributed by 29AjayKumar
Output List After inserting 3 elements: 11 12 13 List After inserting 2 more elements: 11 12 13 14 15




Article Tags :
Data Structures
Linked List
circular linked list
doubly linked list
Linked Lists
Practice Tags :
Data Structures
Linked List
circular linked list
Read Full Article

Move last element to front of a given Linked List

Write a function that moves the last element to the front in a given Singly Linked List. For example, if the given Linked List is 1->2->3->4->5, then the function should change the list to 5->1->2->3->4.

Algorithm:
Traverse the list till last node. Use two pointers: one to store the address of last node and other for address of second last node. After the end of loop do following operations.
i] Make second last as last [secLast->next = NULL].
ii] Set next of last as head [last->next = *head_ref].
iii] Make last as head [ *head_ref = last]

C++




/* CPP Program to move last element
to front in a given linked list */
#include
using namespace std;
/* A linked list node */
class Node
{
public:
int data;
Node *next;
};
/* We are using a double pointer
head_ref here because we change
head of the linked list inside
this function.*/
void moveToFront[Node **head_ref]
{
/* If linked list is empty, or
it contains only one node,
then nothing needs to be done,
simply return */
if [*head_ref == NULL || [*head_ref]->next == NULL]
return;
/* Initialize second last
and last pointers */
Node *secLast = NULL;
Node *last = *head_ref;
/*After this loop secLast contains
address of second last node and
last contains address of last node in Linked List */
while [last->next != NULL]
{
secLast = last;
last = last->next;
}
/* Set the next of second last as NULL */
secLast->next = NULL;
/* Set next of last as head node */
last->next = *head_ref;
/* Change the head pointer
to point to last node now */
*head_ref = last;
}
/* UTILITY FUNCTIONS */
/* Function to add a node
at the beginning of Linked List */
void push[Node** head_ref, int new_data]
{
/* allocate node */
Node* new_node = new Node[];
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = [*head_ref];
/* move the head to point to the new node */
[*head_ref] = new_node;
}
/* Function to print nodes in a given linked list */
void printList[Node *node]
{
while[node != NULL]
{
cout data next;
}
}
/* Driver code */
int main[]
{
Node *start = NULL;
/* The constructed linked list is:
1->2->3->4->5 */
push[&start, 5];
push[&start, 4];
push[&start, 3];
push[&start, 2];
push[&start, 1];
coutnext = NULL;
/* Set next of last as head node */
last->next = *head_ref;
/* Change the head pointer to point to last node now */
*head_ref = last;
}
/* UTILITY FUNCTIONS */
/* Function to add a node at the beginning of Linked List */
void push[struct Node** head_ref, int new_data]
{
/* allocate node */
struct Node* new_node =
[struct Node*] malloc[sizeof[struct Node]];
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = [*head_ref];
/* move the head to point to the new node */
[*head_ref] = new_node;
}
/* Function to print nodes in a given linked list */
void printList[struct Node *node]
{
while[node != NULL]
{
printf["%d ", node->data];
node = node->next;
}
}
/* Driver program to test above function */
int main[]
{
struct Node *start = NULL;
/* The constructed linked list is:
1->2->3->4->5 */
push[&start, 5];
push[&start, 4];
push[&start, 3];
push[&start, 2];
push[&start, 1];
printf["\n Linked list before moving last to front\n"];
printList[start];
moveToFront[&start];
printf["\n Linked list after removing last to front\n"];
printList[start];
return 0;
}
Java




/* Java Program to move last element to front in a given linked list */
class LinkedList
{
Node head; // head of list
/* Linked list Node*/
class Node
{
int data;
Node next;
Node[int d] {data = d; next = null; }
}
void moveToFront[]
{
/* If linked list is empty or it contains only
one node then simply return. */
if[head == null || head.next == null]
return;
/* Initialize second last and last pointers */
Node secLast = null;
Node last = head;
/* After this loop secLast contains address of
second last node and last contains address of
last node in Linked List */
while [last.next != null]
{
secLast = last;
last = last.next;
}
/* Set the next of second last as null */
secLast.next = null;
/* Set the next of last as head */
last.next = head;
/* Change head to point to last node. */
head = last;
}
/* Utility functions */
/* Inserts a new Node at front of the list. */
public void push[int new_data]
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node[new_data];
/* 3. Make next of new Node as head */
new_node.next = head;
/* 4. Move the head to point to new Node */
head = new_node;
}
/* Function to print linked list */
void printList[]
{
Node temp = head;
while[temp != null]
{
System.out.print[temp.data+" "];
temp = temp.next;
}
System.out.println[];
}
/* Driver program to test above functions */
public static void main[String args[]]
{
LinkedList llist = new LinkedList[];
/* Constructed Linked List is 1->2->3->4->5->null */
llist.push[5];
llist.push[4];
llist.push[3];
llist.push[2];
llist.push[1];
System.out.println["Linked List before moving last to front "];
llist.printList[];
llist.moveToFront[];
System.out.println["Linked List after moving last to front "];
llist.printList[];
}
}
/* This code is contributed by Rajat Mishra */
Python3




# Python3 code to move the last item to front
class Node:
def __init__[self, data]:
self.data = data
self.next = None
class LinkedList:
def __init__[self]:
self.head = None
# Function to add a node
# at the beginning of Linked List
def push[self, data]:
new_node = Node[data]
new_node.next = self.head
self.head = new_node
# Function to print nodes in a
# given linked list
def printList[self]:
tmp = self.head
while tmp is not None:
print[tmp.data, end=", "]
tmp = tmp.next
print[]
# Function to bring the last node to the front
def moveToFront[self]:
tmp = self.head
sec_last = None # To maintain the track of
# the second last node
# To check whether we have not received
# the empty list or list with a single node
if not tmp or not tmp.next:
return
# Iterate till the end to get
# the last and second last node
while tmp and tmp.next :
sec_last = tmp
tmp = tmp.next
# point the next of the second
# last node to None
sec_last.next = None
# Make the last node as the first Node
tmp.next = self.head
self.head = tmp
# Driver Code
if __name__ == '__main__':
llist = LinkedList[]
# swap the 2 nodes
llist.push[5]
llist.push[4]
llist.push[3]
llist.push[2]
llist.push[1]
print ["Linked List before moving last to front "]
llist.printList[]
llist.moveToFront[]
print ["Linked List after moving last to front "]
llist.printList[]
C#




/* C# Program to move last element to front in a given linked list */
using System;
class LinkedList
{
Node head; // head of list
/* Linked list Node*/
public class Node
{
public int data;
public Node next;
public Node[int d] {data = d; next = null; }
}
void moveToFront[]
{
/* If linked list is empty or it contains only
one node then simply return. */
if[head == null || head.next == null]
return;
/* Initialize second last and last pointers */
Node secLast = null;
Node last = head;
/* After this loop secLast contains address of
second last node and last contains address of
last node in Linked List */
while [last.next != null]
{
secLast = last;
last = last.next;
}
/* Set the next of second last as null */
secLast.next = null;
/* Set the next of last as head */
last.next = head;
/* Change head to point to last node. */
head = last;
}
/* Utility functions */
/* Inserts a new Node at front of the list. */
public void push[int new_data]
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node[new_data];
/* 3. Make next of new Node as head */
new_node.next = head;
/* 4. Move the head to point to new Node */
head = new_node;
}
/* Function to print linked list */
void printList[]
{
Node temp = head;
while[temp != null]
{
Console.Write[temp.data+" "];
temp = temp.next;
}
Console.WriteLine[];
}
/* Driver program to test above functions */
public static void Main[String []args]
{
LinkedList llist = new LinkedList[];
/* Constructed Linked List is 1->2->3->4->5->null */
llist.push[5];
llist.push[4];
llist.push[3];
llist.push[2];
llist.push[1];
Console.WriteLine["Linked List before moving last to front "];
llist.printList[];
llist.moveToFront[];
Console.WriteLine["Linked List after moving last to front "];
llist.printList[];
}
}
// This code is contributed by Arnab Kundu
Javascript




/* javascript Program to move last element to front in a given linked list */
/* Linked list Node */
class Node {
constructor[val] {
this.data = val;
this.next = null;
}
}
var head; // head of list
function moveToFront[] {
/*
* If linked list is empty or it contains only one node then simply return.
*/
if [head == null || head.next == null]
return;
/* Initialize second last and last pointers */
var secLast = null;
var last = head;
/*
* After this loop secLast contains address of second last node and last
* contains address of last node in Linked List
*/
while [last.next != null] {
secLast = last;
last = last.next;
}
/* Set the next of second last as null */
secLast.next = null;
/* Set the next of last as head */
last.next = head;
/* Change head to point to last node. */
head = last;
}
/* Utility functions */
/* Inserts a new Node at front of the list. */
function push[new_data] {
/*
* 1 & 2: Allocate the Node & Put in the data
*/
var new_node = new Node[new_data];
/* 3. Make next of new Node as head */
new_node.next = head;
/* 4. Move the head to point to new Node */
head = new_node;
}
/* Function to print linked list */
function printList[] {
var temp = head;
while [temp != null] {
document.write[temp.data + " "];
temp = temp.next;
}
document.write[];
}
/* Driver program to test above functions */
/* Constructed Linked List is 1->2->3->4->5->null */
push[5];
push[4];
push[3];
push[2];
push[1];
document.write["Linked List before moving last to front
"];
printList[];
moveToFront[];
document.write["
Linked List after moving last to front
"];
printList[];
// This code is contributed by umadevi9616

Output:

Linked list before moving last to front 1 2 3 4 5 Linked list after removing last to front 5 1 2 3 4

Time Complexity: O[n] where n is the number of nodes in the given Linked List.

?list=PLqM7alHXFySH41ZxzrPNj2pAYPOI8ITe7
Please write comments if you find any bug in the above code/algorithm, or find other ways to solve the same problem.




Article Tags :
Linked List
Practice Tags :
Linked List
Read Full Article

Types of Linked List

Before knowing about the types of a linked list, we should know what is linked list. So, to know about the linked list, click on the link given below:

Circular Doubly Linked List

Circular doubly linked list is a more complexed type of data structure in which a node contain pointers to its previous node as well as the next node. Circular doubly linked list doesn't contain NULL in any of the node. The last node of the list contains the address of the first node of the list. The first node of the list also contain address of the last node in its previous pointer.

A circular doubly linked list is shown in the following figure.



Due to the fact that a circular doubly linked list contains three parts in its structure therefore, it demands more space per node and more expensive basic operations. However, a circular doubly linked list provides easy manipulation of the pointers and the searching becomes twice as efficient.

Basic concepts and nomenclatureEdit

Each record of a linked list is often called an 'element' or 'node'.

The field of each node that contains the address of the next node is usually called the 'next link' or 'next pointer'. The remaining fields are known as the 'data', 'information', 'value', 'cargo', or 'payload' fields.

The 'head' of a list is its first node. The 'tail' of a list may refer either to the rest of the list after the head, or to the last node in the list. In Lisp and some derived languages, the next node may be called the 'cdr' [pronounced could-er] of the list, while the payload of the head node may be called the 'car'.

Singly linked listEdit

Singly linked lists contain nodes which have a data field as well as 'next' field, which points to the next node in line of nodes. Operations that can be performed on singly linked lists include insertion, deletion and traversal.

A singly linked list whose nodes contain two fields: an integer value and a link to the next node

The following code demonstrates how to add a new node with data "value" to the end of a singly linked list:

node addNode[node head, int value] { node temp, p; // declare two nodes temp and p temp = createNode[]; // assume createNode creates a new node with data = 0 and next pointing to NULL. temp->data = value; // add element's value to data part of node if [head == NULL] { head = temp; // when linked list is empty } else { p = head; // assign head to p while [p->next != NULL] { p = p->next; // traverse the list until p is the last node. The last node always points to NULL. } p->next = temp; // Point the previous last node to the new node created. } return head; }

Doubly linked listEdit

In a 'doubly linked list', each node contains, besides the next-node link, a second link field pointing to the 'previous' node in the sequence. The two links may be called 'forward['s'] and 'backwards', or 'next' and 'prev'['previous'].

A doubly linked list whose nodes contain three fields: an integer value, the link forward to the next node, and the link backward to the previous node

A technique known as XOR-linking allows a doubly linked list to be implemented using a single link field in each node. However, this technique requires the ability to do bit operations on addresses, and therefore may not be available in some high-level languages.

Many modern operating systems use doubly linked lists to maintain references to active processes, threads, and other dynamic objects.[2] A common strategy for rootkits to evade detection is to unlink themselves from these lists.[3]

Multiply linked listEdit

In a 'multiply linked list', each node contains two or more link fields, each field being used to connect the same set of data records in a different order of same set [e.g., by name, by department, by date of birth, etc.]. While doubly linked lists can be seen as special cases of multiply linked list, the fact that the two and more orders are opposite to each other leads to simpler and more efficient algorithms, so they are usually treated as a separate case.

Circular linked listEdit

In the last node of a list, the link field often contains a null reference, a special value is used to indicate the lack of further nodes. A less common convention is to make it point to the first node of the list; in that case, the list is said to be 'circular' or 'circularly linked'; otherwise, it is said to be 'open' or 'linear'. It is a list where the last pointer points to the first node.

In the case of a circular doubly linked list, the first node also points to the last node of the list.

Sentinel nodesEdit

In some implementations an extra 'sentinel' or 'dummy' node may be added before the first data record or after the last one. This convention simplifies and accelerates some list-handling algorithms, by ensuring that all links can be safely dereferenced and that every list [even one that contains no data elements] always has a "first" and "last" node.

Empty listsEdit

An empty list is a list that contains no data records. This is usually the same as saying that it has zero nodes. If sentinel nodes are being used, the list is usually said to be empty when it has only sentinel nodes.

Hash linkingEdit

The link fields need not be physically part of the nodes. If the data records are stored in an array and referenced by their indices, the link field may be stored in a separate array with the same indices as the data records.

List handlesEdit

Since a reference to the first node gives access to the whole list, that reference is often called the 'address', 'pointer', or 'handle' of the list. Algorithms that manipulate linked lists usually get such handles to the input lists and return the handles to the resulting lists. In fact, in the context of such algorithms, the word "list" often means "list handle". In some situations, however, it may be convenient to refer to a list by a handle that consists of two links, pointing to its first and last nodes.

Combining alternativesEdit

The alternatives listed above may be arbitrarily combined in almost every way, so one may have circular doubly linked lists without sentinels, circular singly linked lists with sentinels, etc.

TradeoffsEdit

As with most choices in computer programming and design, no method is well suited to all circumstances. A linked list data structure might work well in one case, but cause problems in another. This is a list of some of the common tradeoffs involving linked list structures.

Linked lists vs. dynamic arraysEdit

A dynamic array is a data structure that allocates all elements contiguously in memory, and keeps a count of the current number of elements. If the space reserved for the dynamic array is exceeded, it is reallocated and [possibly] copied, which is an expensive operation.

Linked lists have several advantages over dynamic arrays. Insertion or deletion of an element at a specific point of a list, assuming that we have indexed a pointer to the node [before the one to be removed, or before the insertion point] already, is a constant-time operation [otherwise without this reference it is O[n]], whereas insertion in a dynamic array at random locations will require moving half of the elements on average, and all the elements in the worst case. While one can "delete" an element from an array in constant time by somehow marking its slot as "vacant", this causes fragmentation that impedes the performance of iteration.

Moreover, arbitrarily many elements may be inserted into a linked list, limited only by the total memory available; while a dynamic array will eventually fill up its underlying array data structure and will have to reallocate—an expensive operation, one that may not even be possible if memory is fragmented, although the cost of reallocation can be averaged over insertions, and the cost of an insertion due to reallocation would still be amortized O[1]. This helps with appending elements at the array's end, but inserting into [or removing from] middle positions still carries prohibitive costs due to data moving to maintain contiguity. An array from which many elements are removed may also have to be resized in order to avoid wasting too much space.

On the other hand, dynamic arrays [as well as fixed-size array data structures] allow constant-time random access, while linked lists allow only sequential access to elements. Singly linked lists, in fact, can be easily traversed in only one direction. This makes linked lists unsuitable for applications where it's useful to look up an element by its index quickly, such as heapsort. Sequential access on arrays and dynamic arrays is also faster than on linked lists on many machines, because they have optimal locality of reference and thus make good use of data caching.

Another disadvantage of linked lists is the extra storage needed for references, which often makes them impractical for lists of small data items such as characters or boolean values, because the storage overhead for the links may exceed by a factor of two or more the size of the data. In contrast, a dynamic array requires only the space for the data itself [and a very small amount of control data].[note 1] It can also be slow, and with a naïve allocator, wasteful, to allocate memory separately for each new element, a problem generally solved using memory pools.

Some hybrid solutions try to combine the advantages of the two representations. Unrolled linked lists store several elements in each list node, increasing cache performance while decreasing memory overhead for references. CDR coding does both these as well, by replacing references with the actual data referenced, which extends off the end of the referencing record.

A good example that highlights the pros and cons of using dynamic arrays vs. linked lists is by implementing a program that resolves the Josephus problem. The Josephus problem is an election method that works by having a group of people stand in a circle. Starting at a predetermined person, one may count around the circle n times. Once the nth person is reached, one should remove them from the circle and have the members close the circle. The process is repeated until only one person is left. That person wins the election. This shows the strengths and weaknesses of a linked list vs. a dynamic array, because if the people are viewed as connected nodes in a circular linked list, then it shows how easily the linked list is able to delete nodes [as it only has to rearrange the links to the different nodes]. However, the linked list will be poor at finding the next person to remove and will need to search through the list until it finds that person. A dynamic array, on the other hand, will be poor at deleting nodes [or elements] as it cannot remove one node without individually shifting all the elements up the list by one. However, it is exceptionally easy to find the nth person in the circle by directly referencing them by their position in the array.

The list ranking problem concerns the efficient conversion of a linked list representation into an array. Although trivial for a conventional computer, solving this problem by a parallel algorithm is complicated and has been the subject of much research.

A balanced tree has similar memory access patterns and space overhead to a linked list while permitting much more efficient indexing, taking O[log n] time instead of O[n] for a random access. However, insertion and deletion operations are more expensive due to the overhead of tree manipulations to maintain balance. Schemes exist for trees to automatically maintain themselves in a balanced state: AVL trees or red–black trees.

Singly linked linear lists vs. other listsEdit

While doubly linked and circular lists have advantages over singly linked linear lists, linear lists offer some advantages that make them preferable in some situations.

A singly linked linear list is a recursive data structure, because it contains a pointer to a smaller object of the same type. For that reason, many operations on singly linked linear lists [such as merging two lists, or enumerating the elements in reverse order] often have very simple recursive algorithms, much simpler than any solution using iterative commands. While those recursive solutions can be adapted for doubly linked and circularly linked lists, the procedures generally need extra arguments and more complicated base cases.

Linear singly linked lists also allow tail-sharing, the use of a common final portion of sub-list as the terminal portion of two different lists. In particular, if a new node is added at the beginning of a list, the former list remains available as the tail of the new one—a simple example of a persistent data structure. Again, this is not true with the other variants: a node may never belong to two different circular or doubly linked lists.

In particular, end-sentinel nodes can be shared among singly linked non-circular lists. The same end-sentinel node may be used for every such list. In Lisp, for example, every proper list ends with a link to a special node, denoted by nil or [], whose CAR and CDR links point to itself. Thus a Lisp procedure can safely take the CAR or CDR of any list.

The advantages of the fancy variants are often limited to the complexity of the algorithms, not in their efficiency. A circular list, in particular, can usually be emulated by a linear list together with two variables that point to the first and last nodes, at no extra cost.

Doubly linked vs. singly linkedEdit

Double-linked lists require more space per node [unless one uses XOR-linking], and their elementary operations are more expensive; but they are often easier to manipulate because they allow fast and easy sequential access to the list in both directions. In a doubly linked list, one can insert or delete a node in a constant number of operations given only that node's address. To do the same in a singly linked list, one must have the address of the pointer to that node, which is either the handle for the whole list [in case of the first node] or the link field in the previous node. Some algorithms require access in both directions. On the other hand, doubly linked lists do not allow tail-sharing and cannot be used as persistent data structures.

Circularly linked vs. linearly linkedEdit

A circularly linked list may be a natural option to represent arrays that are naturally circular, e.g. the corners of a polygon, a pool of buffers that are used and released in FIFO ["first in, first out"] order, or a set of processes that should be time-shared in round-robin order. In these applications, a pointer to any node serves as a handle to the whole list.

With a circular list, a pointer to the last node gives easy access also to the first node, by following one link. Thus, in applications that require access to both ends of the list [e.g., in the implementation of a queue], a circular structure allows one to handle the structure by a single pointer, instead of two.

A circular list can be split into two circular lists, in constant time, by giving the addresses of the last node of each piece. The operation consists in swapping the contents of the link fields of those two nodes. Applying the same operation to any two nodes in two distinct lists joins the two list into one. This property greatly simplifies some algorithms and data structures, such as the quad-edge and face-edge.

The simplest representation for an empty circular list [when such a thing makes sense] is a null pointer, indicating that the list has no nodes. Without this choice, many algorithms have to test for this special case, and handle it separately. By contrast, the use of null to denote an empty linear list is more natural and often creates fewer special cases.

For some applications, it can be useful to use singly linked lists that can vary between being circular and being linear, or even circular with a linear initial segment. Algorithms for searching or otherwise operating on these have to take precautions to avoid accidentally entering an endless loop. One usual method is to have a second pointer walking the list at half or double the speed, and if both pointers meet at the same node, you know you found a cycle.

Using sentinel nodesEdit

Sentinel node may simplify certain list operations, by ensuring that the next or previous nodes exist for every element, and that even empty lists have at least one node. One may also use a sentinel node at the end of the list, with an appropriate data field, to eliminate some end-of-list tests. For example, when scanning the list looking for a node with a given value x, setting the sentinel's data field to x makes it unnecessary to test for end-of-list inside the loop. Another example is the merging two sorted lists: if their sentinels have data fields set to +∞, the choice of the next output node does not need special handling for empty lists.

However, sentinel nodes use up extra space [especially in applications that use many short lists], and they may complicate other operations [such as the creation of a new empty list].

However, if the circular list is used merely to simulate a linear list, one may avoid some of this complexity by adding a single sentinel node to every list, between the last and the first data nodes. With this convention, an empty list consists of the sentinel node alone, pointing to itself via the next-node link. The list handle should then be a pointer to the last data node, before the sentinel, if the list is not empty; or to the sentinel itself, if the list is empty.

The same trick can be used to simplify the handling of a doubly linked linear list, by turning it into a circular doubly linked list with a single sentinel node. However, in this case, the handle should be a single pointer to the dummy node itself.[8]

Video liên quan

Bài Viết Liên Quan

Bài mới nhất

Chủ Đề