Python program to remove Nth occurrence of the given word
Given a list of words in Python, the task is to remove the Nth occurrence of the given word in that list.
Examples:
Recommended: Please try your approach on {IDE} first, before moving on to the solution.
Approach #1: By taking another list.
Make a new list, say newList. Iterate the elements in the list and check if the word to be removed matches the element and the occurrence number, otherwise, append the element to newList.
Python3
|
# Python3 program to remove Nth
# occurrence of the given word
# Function to remove Ith word
def RemoveIthWord[lst, word, N]:
newList = []
count = 0
# iterate the elements
for i in lst:
if[i == word]:
count = count + 1
if[count != N]:
newList.append[i]
else:
newList.append[i]
lst = newList
if count == 0:
print["Item not found"]
else:
print["Updated list is: ", lst]
return newList
# Driver code
list = ["geeks", "for", "geeks"]
word = "geeks"
N = 2
RemoveIthWord[list, word, N]
|
Output :
Updated list is: ['geeks', 'for']
Approach #2: Remove from the list itself.
Instead of making a new list, delete the matching element from the list itself. Iterate the elements in the list and check if the word to be removed matches the element and the occurrence number, If yes delete that item and return true. If True is returned, print List otherwise, print “Item not Found”.
Python3
|
# Python3 program to remove Nth
# occurrence of the given word
# Function to remove Ith word
def RemoveIthWord[list, word, N]:
count = 0
for i in range[0, len[list]]:
if [list[i] == word]:
count = count + 1
if[count == N]:
del[list[i]]
return True
return False
# Driver code
list = ['geeks', 'for', 'geeks']
word = 'geeks'
N = 2
flag = RemoveIthWord[list, word, N]
if [flag == True]:
print["Updated list is: ", list]
else:
print["Item not Updated"]
|
Output :
Updated list is: ['geeks', 'for']Approach #3: Remove from the list using pop[].
Instead of creating a new list and using if/else statement we can pop the matching element from the list using pop[ ]. We need to use an additional counter to keep track of the index.
Why we need an index ? because pop[ ] needs index to pass inside i.e pop[index].
Python3
|
# Python3 program to remove Nth
# occurrence of the given word
# Function to remove nth word
def omit[list1,word,n1]:
# for counting the occurrence of word
count=0
# for counting the index number
# where we are at present
index=0
for i in list1:
index+=1
if i==word:
count+=1
if count==n1:
# [index-1] because in list
# indexing start from 0th position
list1.pop[index-1]
return list1
# Driver code
list1 = ["he", "is", "ankit", "is",
"raj", "is","ankit raj"]
word="is"
n1=3
print["new list is :",omit[list1,word,n1]]
|
Output :
new list is : ['he', 'is', 'ankit', 'is', 'raj', 'ankit raj']Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.
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Article Tags :
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Python program to remove nth occurrence of the given word list
- To allow the user to input a number of elements in the list and store it in a variable.
- Accept the values into the list using a for loop and insert them into the python list.
- Use a for loop to traverse through the elements in the list.
- Then use an if statement to check if the word to be removed matches the element and the occurrence number and otherwise, it appends the element to another list.
- The number of repetitions along with the updated list and distinct elements is printed.
# python program to remove nth occurrence of the given word
a=[]
n= int[input["Enter the number of elements in list:"]]
for x in range[0,n]:
element=input["Enter element" + str[x+1] + ":"]
a.append[element]
print[a]
c=[]
count=0
b=input["Enter word to remove: "]
n=int[input["Enter the occurrence to remove: "]]
for i in a:
if[i==b]:
count=count+1
if[count!=n]:
c.append[i]
else:
c.append[i]
if[count==0]:
print["Item not found "]
else:
print["The number of repetitions is: ",count]
print["Updated list is: ",c]
print["The distinct elements are: ",set[a]]
After executing the program, the output will be:
Enter the number of elements in list: 5 Enter element1: test Enter element2: test Enter element3: my Enter element4: world Enter element5: world ['test', 'test', 'my', 'world', 'world'] Enter word to remove: world Enter the occurrence to remove: 4 The number of repetitions is: 2 Updated list is: ['test', 'test', 'my', 'world', 'world'] The distinct elements are: {'test', 'world', 'my'}Python Program to Remove the ith Occurrence of the Given Word in a List where Words can Repeat
There are numerous methods for reading a list of words and removing the ith occurrence of the given word in a list where words can repeat themselves.
- Reading a list of words separated by new line and using count [User Input]
- Reading a list of words separated by space and using count [User Input]
Explore more instances related to python concepts fromPython Programming ExamplesGuide and get promoted from beginner to professional programmer level in Python Programming Language.
Method #1: Reading a list of words separated by new line and using count [User Input]
Approach:
- Scan the number of elements/strings and store it in a variable
- Take a new list say anslist
- Take a count and initialize it to 0
- Using a for loop, accept the values into the list and put them into the list.
- Then use an if statement to check that the term that will be removed coincides with the element and the occurrence number.
- If it matches then increment the count
- If the count doesn’t matches with the occurrence value then append it to anslist.
- Print the anslist.
Below is the implementation:
# Taking a empty list listWords = [] # Taking an empty list which gives the result say anslist anslist = [] # taking a word count and initalize it to 0 wordCount = 0 # scanning the number of strings numb = int[input["enter the total number of strings :"]] # Using for loop for i in range[numb]: elem = input["enter some random string or word :\n"] listWords.append[elem] # given word given_word = input["Enter the word which you want to remove the ith occurrence"] # given occurrence number occur = int[ input["Enter which occurrence you wish to delete of the provided term"]] # printing the list before removing the ith occurrence of word print["printing the list before removing the ith occurrence of word :"] print[listWords] # Traversing the given listWords for word in listWords: # checking if the given word mathches with the word if[word == given_word]: # increasing the count wordCount = wordCount+1 # If the count doesn't matches with the occurrence value then append it to anslist. if[wordCount != occur]: anslist.append[word] else: anslist.append[word] # printing the list before after the ith occurrence of word print["printing the list after removing the ith occurrence of word :"] print[anslist]Output:
enter the total number of strings :8 enter some random string or word : hello enter some random string or word : this enter some random string or word : is enter some random string or word : btechgeeks enter some random string or word : this enter some random string or word : online enter some random string or word : this enter some random string or word : platform Enter the word which you want to remove the ith occurrence = this Enter which occurrence you wish to delete of the provided term = 2 printing the list before removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeeks', 'this', 'online', 'this', 'platform'] printing the list after removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeeks', 'online', 'this', 'platform']Method #2: Reading a list of words separated by space and using count [User Input]
Approach:
- Scan the list of words separated by space .
- Store the above string in list using split[] function.
- Take a new list say anslist
- Take a count and initialize it to 0
- Using a for loop, accept the values into the list and put them into the list.
- Then use an if statement to check that the term that will be removed coincides with the element and the occurrence number.
- If it matches then increment the count
- If the count doesn’t matches with the occurrence value then append it to anslist.
- Print the anslist.
Below is the implementation:
# Taking an empty list which gives the result say anslist anslist = [] # taking a word count and initalize it to 0 wordCount = 0 # Taking a list of words in list using split listWords = list[ input["Enter the list of words / enter the sentence\n"].split[]] # given word given_word = input[ "Enter the word which yoou want to remove the ith occurrence"] # given occurrence number occur = int[ input["Enter which occurrence you wish to delete of the provided term"]] # printing the list before removing the ith occurrence of word print["printing the list before removing the ith occurrence of word :"] print[listWords] # Traversing the given listWords for word in listWords: # checking if the given word mathches with the word if[word == given_word]: # increasing the count wordCount = wordCount+1 # If the count doesn't matches with the occurrence value then append it to anslist. if[wordCount != occur]: anslist.append[word] else: anslist.append[word] # printing the list before after the ith occurrence of word print["printing the list after removing the ith occurrence of word :"] print[anslist]Output:
Enter the list of words / enter the sentence hello this is btechgeeks online this platform this Enter the word which yoou want to remove the ith occurrence = this Enter which occurrence you wish to delete of the provided term =2 printing the list before removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeejsks', 'this', 'is', 'online', 'this', 'platform', 'this'] printing the list after removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeejsks', 'is', 'online', 'this', 'platform', 'this']Related Programs:
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“write a python program to remove the ith occurrence of the given word in a list where words can repeated.” Code Answer
remove all occurrences of a character in a list python
python by Shaunak on Jun 04 2020 Comment
3
Source: stackoverflow.com
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Python Program to Remove the nth Occurrence of the Given Word in a List where Words can Repeat
PythonServer Side ProgrammingProgramming
When it is required to remove a specific occurrence of a given word in a list of words, given that the words can be repeated, a method can be defined, that iterates through the list, and increments the counter by 1. If the count and the specific occurrence match, then the specific element from the list can be deleted.
Below is a demonstration of the same −
Python Program to Remove the ith Occurrence of the Given Word in a List where Words can Repeat
There are numerous methods for reading a list of words and removing the ith occurrence of the given word in a list where words can repeat themselves.
- Reading a list of words separated by new line and using count [User Input]
- Reading a list of words separated by space and using count [User Input]
Explore more instances related to python concepts fromPython Programming ExamplesGuide and get promoted from beginner to professional programmer level in Python Programming Language.
Method #1: Reading a list of words separated by new line and using count [User Input]
Approach:
- Scan the number of elements/strings and store it in a variable
- Take a new list say anslist
- Take a count and initialize it to 0
- Using a for loop, accept the values into the list and put them into the list.
- Then use an if statement to check that the term that will be removed coincides with the element and the occurrence number.
- If it matches then increment the count
- If the count doesn’t matches with the occurrence value then append it to anslist.
- Print the anslist.
Below is the implementation:
# Taking a empty list listWords = [] # Taking an empty list which gives the result say anslist anslist = [] # taking a word count and initalize it to 0 wordCount = 0 # scanning the number of strings numb = int[input["enter the total number of strings :"]] # Using for loop for i in range[numb]: elem = input["enter some random string or word :\n"] listWords.append[elem] # given word given_word = input["Enter the word which you want to remove the ith occurrence"] # given occurrence number occur = int[ input["Enter which occurrence you wish to delete of the provided term"]] # printing the list before removing the ith occurrence of word print["printing the list before removing the ith occurrence of word :"] print[listWords] # Traversing the given listWords for word in listWords: # checking if the given word mathches with the word if[word == given_word]: # increasing the count wordCount = wordCount+1 # If the count doesn't matches with the occurrence value then append it to anslist. if[wordCount != occur]: anslist.append[word] else: anslist.append[word] # printing the list before after the ith occurrence of word print["printing the list after removing the ith occurrence of word :"] print[anslist]Output:
enter the total number of strings :8 enter some random string or word : hello enter some random string or word : this enter some random string or word : is enter some random string or word : btechgeeks enter some random string or word : this enter some random string or word : online enter some random string or word : this enter some random string or word : platform Enter the word which you want to remove the ith occurrence = this Enter which occurrence you wish to delete of the provided term = 2 printing the list before removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeeks', 'this', 'online', 'this', 'platform'] printing the list after removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeeks', 'online', 'this', 'platform']Method #2: Reading a list of words separated by space and using count [User Input]
Approach:
- Scan the list of words separated by space .
- Store the above string in list using split[] function.
- Take a new list say anslist
- Take a count and initialize it to 0
- Using a for loop, accept the values into the list and put them into the list.
- Then use an if statement to check that the term that will be removed coincides with the element and the occurrence number.
- If it matches then increment the count
- If the count doesn’t matches with the occurrence value then append it to anslist.
- Print the anslist.
Below is the implementation:
# Taking an empty list which gives the result say anslist anslist = [] # taking a word count and initalize it to 0 wordCount = 0 # Taking a list of words in list using split listWords = list[ input["Enter the list of words / enter the sentence\n"].split[]] # given word given_word = input[ "Enter the word which yoou want to remove the ith occurrence"] # given occurrence number occur = int[ input["Enter which occurrence you wish to delete of the provided term"]] # printing the list before removing the ith occurrence of word print["printing the list before removing the ith occurrence of word :"] print[listWords] # Traversing the given listWords for word in listWords: # checking if the given word mathches with the word if[word == given_word]: # increasing the count wordCount = wordCount+1 # If the count doesn't matches with the occurrence value then append it to anslist. if[wordCount != occur]: anslist.append[word] else: anslist.append[word] # printing the list before after the ith occurrence of word print["printing the list after removing the ith occurrence of word :"] print[anslist]Output:
Enter the list of words / enter the sentence hello this is btechgeeks online this platform this Enter the word which yoou want to remove the ith occurrence = this Enter which occurrence you wish to delete of the provided term =2 printing the list before removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeejsks', 'this', 'is', 'online', 'this', 'platform', 'this'] printing the list after removing the ith occurrence of word : ['hello', 'this', 'is', 'btechgeejsks', 'is', 'online', 'this', 'platform', 'this']Related Programs:
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