How do you find the uncommon element in two lists in Python?

Python | Uncommon elements in Lists of List

This particular article aims at achieving the task of finding uncommon two list, in which each element is in itself a list. This is also a useful utility as this kind of task can come in life of programmer if he is in the world of development. Lets discuss some ways to achieve this task.

Method 1 : Naive Method
This is the simplest method to achieve this task and uses the brute force approach of executing a loop and to check if one list contains similar list as of the other list, not including that.

Python3




# Python 3 code to demonstrate
# Uncommon elements in List
# using naive method
# initializing lists
test_list1 = [ [1, 2], [3, 4], [5, 6] ]
test_list2 = [ [3, 4], [5, 7], [1, 2] ]
# printing both lists
print ["The original list 1 : " + str[test_list1]]
print ["The original list 2 : " + str[test_list2]]
# using naive method
# Uncommon elements in List
res_list = []
for i in test_list1:
if i not in test_list2:
res_list.append[i]
for i in test_list2:
if i not in test_list1:
res_list.append[i]
# printing the uncommon
print ["The uncommon of two lists is : " + str[res_list]]
Output : The original list 1 : [[1, 2], [3, 4], [5, 6]] The original list 2 : [[3, 4], [5, 7], [1, 2]] The uncommon of two lists is : [[5, 6], [5, 7]]

Method 2 : Using set[] + map[] and ^
The most efficient and recommended method to perform this task is using the combination of set[] and map[] to achieve it. Firstly converting inner lists to tuples using map, and outer lists to set, use of ^ operator can perform the set symmetric difference and hence perform this task. Further if it is required to get in lists of list fashion, we can convert outer and inner containers back to list using map[].

Python3




# Python 3 code to demonstrate
# Uncommon elements in Lists of List
# using map[] + set[] + ^
# initializing lists
test_list1 = [ [1, 2], [3, 4], [5, 6] ]
test_list2 = [ [3, 4], [5, 7], [1, 2] ]
# printing both lists
print ["The original list 1 : " + str[test_list1]]
print ["The original list 2 : " + str[test_list2]]
# using map[] + set[] + ^
# Uncommon elements in Lists of List
res_set = set[map[tuple, test_list1]] ^ set[map[tuple, test_list2]]
res_list = list[map[list, res_set]]
# printing the uncommon
print ["The uncommon of two lists is : " + str[res_list]]
Output : The original list 1 : [[1, 2], [3, 4], [5, 6]] The original list 2 : [[3, 4], [5, 7], [1, 2]] The uncommon of two lists is : [[5, 6], [5, 7]]




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“python find uncommon elements in two lists” Code Answer’s


how to subtract 2 lists in python
python by Velvet Thunder
on Sep 21 2020 Comment
5
Source: stackoverflow.com
get list of words that are in two lists using set
r by Comfortable Cardinal on Nov 21 2020 Comment
0
Source: stackoverflow.com
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how to find uncommon elements in two lists in python
typescript by Brave Buffalo on Mar 15 2021 Comment
0
get list of words that are in two lists using set
r by Comfortable Cardinal on Nov 21 2020 Comment
0
Source: stackoverflow.com
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Find the common elements in two lists in Python

By Shriprakash Tiwari

In this tutorial, We are going to learn how to find the common elements in two lists in Python.
To find the common list from two lists, we have to store the common elements in the third variable. There are various methods to find and store the common elements from two lists.

Using the intersection[] Function

This is the easiest method to find common elements in two lists in Python. As the name suggests, the intersection[] function is a built-in python function that is used to return a set that contains the elements which are common in two sets. The sets can be of any form i.e a list or a dictionary.

Example:

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if __name__ == '__main__':
list_one = [5, 10, 15, 20, 25, 30]
list_two = [10, 20, 30, 40, 50, 60]
common_list = set[list_one].intersection[list_two]
print[common_list]

Output:

{10, 20, 30}

Note that, __name__ variable is used in the above code. It is a built-in variable that is used to see whether the current code is being run on its own or an external module is being imported from somewhere. Thus, the __name__ variable checks the name of the current module in the ongoing code. It is usually used with an if statement and where it is assigned to '__main__' when there is no module in the program. Otherwise, __name__ is assigned to the name of the module used in the program.

1. Using intersection[] function

A simple and fairly efficient solution is to convert the first list into a set and then call the intersection[] function. It returns a new set with elements common to the set with another iterable.

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if __name__ == '__main__':
first = [1, 2, 3, 5]
second = [2, 4, 5, 7]
common = set[first].intersection[second]
print[common]# {2, 5}

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