How do you generate a random number from a List in Java?

1. Introduction

Picking a random List element is a very basic operation but not so obvious to implement. In this article, we'll show the most efficient way of doing this in different contexts.

Randomly select items from a List in Java

In this article, we will show the most efficient way, finding or picking an element from the List.The basic idea for pick an item from the list is, First generate a number that should be between 0 to list size.

1. Single Random Item

First, we select a random index for using Random.nextInt[int bound] method. Instead of Random class, you can always use the static method Math.random[][random[] method generate a number between 0 and 1] and multiply it with list size.

Java




// Java program select a random element from array
import java.util.ArrayList;
import java.util.List;
import java.util.Random;
public class GFG {
// Drive Function
public static void main[String[] args]
{
// create a list of Integer type
List list = new ArrayList[];
// add 5 element in ArrayList
list.add[10];
list.add[20];
list.add[30];
list.add[40];
list.add[50];
GFG obj = new GFG[];
// take a random element from list and print them
System.out.println[obj.getRandomElement[list]];
}
// Function select an element base on index
// and return an element
public int getRandomElement[List list]
{
Random rand = new Random[];
return list.get[rand.nextInt[list.size[]]];
}
}
Output 30

2. Select Random Index In Multithread Environment



When we work with multithread applications using the single Random class instance then might result in picking the same value for every process accessing this instance. Hence, We can always create a new instance per thread by using ThreadLocalRandom class.

Java




// Java program select a random element from List
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ThreadLocalRandom;
public class GFG {
// Drive Function
public static void main[String[] args]
{
// create a list of Integer type
List list = new ArrayList[];
// add 5 element in ArrayList
list.add[10];
list.add[20];
list.add[30];
list.add[40];
list.add[50];
GFG obj = new GFG[];
// boundIndex to select in sub list
int boundIndex = 3;
// take a random element from list and print it
System.out.println[
obj.getRandomElement[list, boundIndex]];
}
// Function to select an element based on index and
// return an element
public int getRandomElement[List list,
int bound]
{
// ThreadLocalRandom generates an int type number
return list.get[
ThreadLocalRandom.current[].nextInt[list.size[]]
% bound];
}
}
Output 10

3. Select Random Items With Repetitions List Element

Sometimes we want to pick a few elements from a list. So first know how much element we want to select after that we select items one by one and add a new list and return it. Note: in this case, one element may be select many times because we are not remove selected elements so the list size remaining the same.

Java




// Java program select a random element from List
import java.util.ArrayList;
import java.util.List;
import java.util.Random;
public class GFG {
// Drive Function
public static void main[String[] args]
{
// create a list of Integer type
List list = new ArrayList[];
// add 5 element in ArrayList
list.add[10];
list.add[20];
list.add[30];
list.add[40];
list.add[50];
GFG obj = new GFG[];
// boundIndex for select in sub list
int numberOfElements = 3;
// take a random element from list and print them
System.out.println[
obj.getRandomElement[list, numberOfElements]];
}
// Function select an element base on index and return
// an element
public List
getRandomElement[List list, int totalItems]
{
Random rand = new Random[];
// create a temporary list for storing
// selected element
List newList = new ArrayList[];
for [int i = 0; i < totalItems; i++] {
// take a random index between 0 to size
// of given List
int randomIndex = rand.nextInt[list.size[]];
// add element in temporary list
newList.add[list.get[randomIndex]];
}
return newList;
}
}
Output [40, 20, 40]

4. Select Random Items Without Repetitions List Element

Sometimes we want to pick a few elements from a list. So first make sure how much element we want to select after that we select items one by one and add a new list and return it. Note: in this case, one element selects only ones because we are remove selected elements, so decrease list size also automatic by JVM.

Java




// Java program select a random element from List
import java.util.ArrayList;
import java.util.List;
import java.util.Random;
public class GFG {
// Drive Function
public static void main[String[] args]
{
// create a list of Integer type
List list = new ArrayList[];
// add 5 element in ArrayList
list.add[10];
list.add[20];
list.add[30];
list.add[40];
list.add[50];
GFG obj = new GFG[];
// boundIndex for select in sub list
int numberOfElements = 3;
// take a random element from list and print them
System.out.println[
obj.getRandomElement[list, numberOfElements]];
}
// Function select an element base on index and return
// an element
public List
getRandomElement[List list, int totalItems]
{
Random rand = new Random[];
// create a temporary list for storing
// selected element
List newList = new ArrayList[];
for [int i = 0; i < totalItems; i++] {
// take a random index between 0 to size
// of given List
int randomIndex = rand.nextInt[list.size[]];
// add element in temporary list
newList.add[list.get[randomIndex]];
// Remove selected element from original list
list.remove[randomIndex];
}
return newList;
}
}
Output [50, 10, 20]




Article Tags :
Java
Technical Scripter
java-list
Java-List-Programs
Technical Scripter 2018
Practice Tags :
Java
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How to generate Random Numbers in Java

Ashish Lahoti
Last Modified: November 25, 2020
Java

In this tutorial, we’ll learn how to generate random number, generate random list, get random number from list, shuffle elements in list using Random Class in Java.

Generating Random Integer Values in Java

Random’s NextInt Method

java.util.Random.nextInt

Java’s Random package has quite a slew of randomization options. Among them: the nextInt[] method. From the official Oracle Documentation:

Returns the next pseudorandom, uniformly distributed int value from this random number generator’s sequence.

This will return a random integer value within the range of all possible [signed] integer values: -2,147,483,648 to 2,147,483,647 [2-31 to 231 – 1]. To learn more about the possible values of Java datatypes read the official Oracle article. That’s great, but what about those times one needs a random integer within a specific range of values? The nextInt[int bound] method has you covered!

Returns a pseudorandom, uniformly distributed int value between 0 [inclusive] and the specified value [exclusive], drawn from this random number generator’s sequence.

Note the “exclusive” part of that documentation. That means the upper bound willnotbe included as an option. This is common among programming languages but important to keep in mind.

Examples

Knowing how the Random.nextInt[] method works is one thing, but knowing how to apply it is another. Below are several examples of how this Java built-in can help address common programming tasks. For all tasks: import java.util.Random;

Generating a Random Integer

int randomInteger= new Random[].nextInt[];

Generating a Random Integer Between 0 and 10

int randomInteger = new Random[].nextInt[10];

Generate a Random Integer in Range [Exclusive Upper Bounds]

// Define min/max int min = 5; intmax=10; // Generates the random integer intrandomInteger=newRandom[].nextInt[[max-min]]+min;

This one deserves a bit of quick discussion to understand on a conceptual level. It can be broken down into two parts:

  1. Generate a number in the range of 0 to [max - min].
  2. Map that number to the range of min to max.

This two-step process can be described as first getting a value from the correctnumber of possibilities and then adding back the minimum to ensure the value is from the correctrange of values. Consider the illustration below:

The first step in selecting a number in a random range is to generate a number from the appropriate number of possible values followed by mapping to the correct range of possible values.

This provides an easy way to produce a random integer value within a specified range. For example, a random number between 1 and 10; a random number between 50 and 100; a random nu… you get the idea.

Java - generate list with 10 random numbers

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