Print the elements of a linked list hackerrank solution C++

Problem solution in Python programming.

#!/bin/python3 import math import os import random import re import sys class SinglyLinkedListNode: def __init__[self, node_data]: self.data = node_data self.next = None class SinglyLinkedList: def __init__[self]: self.head = None self.tail = None def insert_node[self, node_data]: node = SinglyLinkedListNode[node_data] if not self.head: self.head = node else: self.tail.next = node self.tail = node def printLinkedList[head]: curr = head while curr: print[curr.data] curr = curr.next if __name__ == '__main__': llist_count = int[input[]] llist = SinglyLinkedList[] for _ in range[llist_count]: llist_item = int[input[]] llist.insert_node[llist_item] printLinkedList[llist.head]




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