Date Object
The Date object works with dates and times.
Date objects are created with new Date[].
There are four ways of instantiating [creating] a date:
JavaScript Date Methods and Properties
| constructor | Returns the function that created the Date object's prototype |
| getDate[] | Returns the day of the month [from 1-31] |
| getDay[] | Returns the day of the week [from 0-6] |
| getFullYear[] | Returns the year |
| getHours[] | Returns the hour [from 0-23] |
| getMilliseconds[] | Returns the milliseconds [from 0-999] |
| getMinutes[] | Returns the minutes [from 0-59] |
| getMonth[] | Returns the month [from 0-11] |
| getSeconds[] | Returns the seconds [from 0-59] |
| getTime[] | Returns the number of milliseconds since midnight Jan 1 1970, and a specified date |
| getTimezoneOffset[] | Returns the time difference between UTC time and local time, in minutes |
| getUTCDate[] | Returns the day of the month, according to universal time [from 1-31] |
| getUTCDay[] | Returns the day of the week, according to universal time [from 0-6] |
| getUTCFullYear[] | Returns the year, according to universal time |
| getUTCHours[] | Returns the hour, according to universal time [from 0-23] |
| getUTCMilliseconds[] | Returns the milliseconds, according to universal time [from 0-999] |
| getUTCMinutes[] | Returns the minutes, according to universal time [from 0-59] |
| getUTCMonth[] | Returns the month, according to universal time [from 0-11] |
| getUTCSeconds[] | Returns the seconds, according to universal time [from 0-59] |
| getYear[] | Deprecated. Use the getFullYear[] method instead |
| now[] | Returns the number of milliseconds since midnight Jan 1, 1970 |
| parse[] | Parses a date string and returns the number of milliseconds since January 1, 1970 |
| prototype | Allows you to add properties and methods to an object |
| setDate[] | Sets the day of the month of a date object |
| setFullYear[] | Sets the year of a date object |
| setHours[] | Sets the hour of a date object |
| setMilliseconds[] | Sets the milliseconds of a date object |
| setMinutes[] | Set the minutes of a date object |
| setMonth[] | Sets the month of a date object |
| setSeconds[] | Sets the seconds of a date object |
| setTime[] | Sets a date to a specified number of milliseconds after/before January 1, 1970 |
| setUTCDate[] | Sets the day of the month of a date object, according to universal time |
| setUTCFullYear[] | Sets the year of a date object, according to universal time |
| setUTCHours[] | Sets the hour of a date object, according to universal time |
| setUTCMilliseconds[] | Sets the milliseconds of a date object, according to universal time |
| setUTCMinutes[] | Set the minutes of a date object, according to universal time |
| setUTCMonth[] | Sets the month of a date object, according to universal time |
| setUTCSeconds[] | Set the seconds of a date object, according to universal time |
| setYear[] | Deprecated. Use the setFullYear[] method instead |
| toDateString[] | Converts the date portion of a Date object into a readable string |
| toGMTString[] | Deprecated. Use the toUTCString[] method instead |
| toISOString[] | Returns the date as a string, using the ISO standard |
| toJSON[] | Returns the date as a string, formatted as a JSON date |
| toLocaleDateString[] | Returns the date portion of a Date object as a string, using locale conventions |
| toLocaleTimeString[] | Returns the time portion of a Date object as a string, using locale conventions |
| toLocaleString[] | Converts a Date object to a string, using locale conventions |
| toString[] | Converts a Date object to a string |
| toTimeString[] | Converts the time portion of a Date object to a string |
| toUTCString[] | Converts a Date object to a string, according to universal time |
| UTC[] | Returns the number of milliseconds in a date since midnight of January 1, 1970, according to UTC time |
| valueOf[] | Returns the primitive value of a Date object |
How do you subtract a day from a date?
Therefore, you can add or subtract days as easy as adding or minus the number of days in Excel. 1. Select a blank cell you will place the calculating result, type the formula =A2+10, and press the Enter key. Note: For subtracting 10 days from the date, please use this formula =A2–10.
How do I remove time part from JavaScript date?
To remove the time from a date, use the getFullYear[] , getMonth[] and getDate[] methods to get the year, month and date of the given date and pass the results to the Date[] constructor. When values for the time components are not provided, they default to 0 .
How do I subtract days from a date in typescript?
let yesterday=new Date[new Date[]. getTime[] - [1 * 24 * 60 * 60 * 1000]]; let last3days=new Date[new Date[]. getTime[] - [3 * 24 * 60 * 60 * 1000]];
Can you subtract dates in JavaScript?
Use the Math. abs[] Function to Subtract Datetime in JavaScript.